2Fe (s) + 3Cl2 (g) —>2FeCl3 (s) What mass of chlorine gas (C1.) needs to be purchesed to be use up 25.7 grams of Iron

Answer 1

First, chlorine gas is Cl₂, not C1.

2Fe(s) + 3Cl₂(g) ==> 2FeCl₃(s) ... balanced equation

Use dimensional analysis and stoichiometry to answer the question:

25.7 g Fe x 1 mol Fe/55.85 g x 3 mol Cl₂ / 2 mol Fe x 70.9 g Cl₂/mol = 48.9 g Cl₂ needed