on average Americans report spending $151 on food per week with a standard deviation of $11. If they are spending on food follows a normal distribution report an interval that falls with each percent

Question

68%

95%

99.7%

Answer 1

68% of data is within 1 standard deviation of the mean, so interval would be 151 +/- 11

95% of data is within 2 standard deviations of the mean, so interval would be 151 +/- 2*11

99.7% of data is within 3 standard deviations of the mean, so interval would be 151 +/- 3*11