Chemistry hw ideal gases

Question

Calculate the temperature of a 2.34mol gas having a pressure of 250 KPa at a volume of 22.76L. Consider that is an ideal gas.

Answer 1

Ideal gas law: PV = nRT

P = pressure = 250 kPa

V = volume in L = 22.76 L

n = moles = 2.34 mol

R = gas constant = 8.314 LkPa/Kmol

T = temperature in K = ?

Solving for T:

T = PV/nR = (250)(22.76) / (2.34)(8.314)

T = 292K = 19ºC