Calculate the molality of a solution formed by adding 8.20 g NH4Cl to 12.2 g of water

Answer 1

molality = moles solute / kg solvent

moles of solute = 8.20 g NH4Cl x 1 mol NH4Cl / 53.49 g = 0.1533 moles

kg solvent = 12.2 g H2O x 1 kg/1000 g = 0.0122 kg

molality = 0.1533 moles / 0.0122 kg = 12.6 m