A solution of CaCl2 in water forms a mixture that is 35.0% calcium chloride by mass. If the total mass of the mixture is 497.8 g, what masses of CaCl2 and water were used?

Answer 1

Given that the solution is 35.0% CaCl₂ by mass, we simply multiply the total mass by 0.350 (35%) to obtain the mass of CaCl₂.

0.350 x 497.8 g = 174.23 g = 174 g CaCl₂

To find the mass of H₂O, simply subtract the mass of CaCl₂ from the total mass as follows:

mass H₂O = 497.8 g - 174 g = 323.8 g H₂O