Write the equation of the line that is perpendicular to y = 2 x − 3 and that passes through the point ( 3 , 1 2 ).

Answer 1

the perpendicular line has a slope which is the negative inverse of 2, which is -1/2

y=-(1/2)x + b where b is the y intercept. to calculate b, plug in the point (3,12) or maybe you meant (3,1/2)?

12=(-1/2)3 + b

b = 12+3/2 = 27/2

the perpendicular line is y=-x/2 + 27/2 or

x+2y = 27

IF you did mean (3,1/2) then

1/2 = -(1/2)3 + b

b = 2 and the perpendicular line would be

y=-x/2 + 2 or

x+2y=2