
Mark M. answered 02/03/21
Mathematics Teacher - NCLB Highly Qualified
12 cos2 x + 4 cos x - 1 = 0
(2 cos x + 1)(6 cos x - 1) = 0
2 cos x = -1
cos x = -0.5
Or
6 cos x = 1
cos x = 1/6
Abhi P.
asked 02/03/21Use inverse trigonometric functions to find the solutions of the equation that are in the given interval, and approximate the solutions to four decimal places. (Enter your answers as a comma-separated list.)
(cos x)(12 cos x + 4) = 1; [0, 2𝜋)
x =
Mark M. answered 02/03/21
Mathematics Teacher - NCLB Highly Qualified
12 cos2 x + 4 cos x - 1 = 0
(2 cos x + 1)(6 cos x - 1) = 0
2 cos x = -1
cos x = -0.5
Or
6 cos x = 1
cos x = 1/6
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Abhi P.
its incorrect02/03/21