Determine the amount of energy (heat) in joules required to raise the temperature of 7.40 g water from 29.0 ºC to 46 ºC.

Answer 1

Specific heat H2O = 4.184 J/gº

heat = mass x specific heat x change in temperature

q = mC∆T

q = ?

m = 7.40 g

C = 4.184 J/gº

∆T = 46 - 29 = 17º

q = (7.40 g)(4.194 J/gº)(17º)

q = 526 J