J.R. S. answered 02/02/21
Ph.D. University Professor with 10+ years Tutoring Experience
moles CH3OH present = 32.8 g x 1 mol/32 g = 1.025 moles
moles O2 present = 50.8 g x 1 mol/32 g = 1.59 moles
Limiting reactant = CH3OH according to the stoichiometry of 1 mol CH3OH : 1.5 mol O2
764 kJ/mole CH3OH x 1.025 moles CH3OH = 783 kJ heat produced