
Patrick B. answered 01/31/21
Math and computer tutor/teacher
Since ABC is an isoceles triangle with base AB,
AC = BC by defintion
angles CAB = CBA are congruent base angles of
this isocoeles triangle
By angle addition postulate,
angle CAB = angle CAD+angle BAD
AND
angle CBA = angle CBE + angle EBA
Then by substitution/transitive:
angle CAD+angle BAD = angle CBE + angle EBA
However, angle CAD = angle CBE is given
so angle BAD = angle EBA by subtraction property of equality
In summary:
AC = BC
angle CAD = angle CBE
and angle C = angle ACD = angle BCE by reflexive property
the result of the proof follows by ASA