find the equation of the line written in point -slope form that passes through the point (-2,-4) and is perpendicular to the line y=-7x+18

Answer 1

m₂ = –1/m_1, m₁ = –7

m₂ = 1/7

(y – y₁) = m₂(x – x₁)

(y + 4) = (1/7)(x + 2) → point-slope form

Answer 2

Perpendicular lines have slopes whose product is -1, or opposite reciprocals. If the line you want is perpendicular to y = -7x + 18, the slope is 1/7.

Point-slope form is

y-y_1 = m(x-x_1),

where m is the slope and (x_1, y_1) are coordinates of a point on the line - in this case, (-2,-4).

Substituting:

y-(-4)=1/7(x-(-2))

or

y+4=1/7(x+2).

Nice of them to ask for it in point-slope form so you don't even have to transform to slope-intercept!