Find: PR . . . . .. . . . . .

Question

Given: △PQR, Area of △PQR = 50

m∠Q=90°, m∠P=36° Find: PR

Answer 1

2 ways to see this

The area of a triangle is (1/2) the product of sides and the sin of the angle between them

One side is 50 cos 36, the other side is 50 => area = (1/2)*50 cos 36 * sin 36

Other way one leg is 50 sin 36 the other is 50 cos 36, the area is is the same as given above.