what is the sum of the angle measures of a 32-gon?

Answer 1

SUm of interior angles = (N-2)*180 where N is the # of sides

triangle: N=3 --> (3-2)*180 = 180

quad : N=4 --> (4-2)*180 = 2*180 = 360

N=32 --> (32-2)*180 = 30*180 = 5400