Inactive Tutor answered 02/25/15
Tutor
New to Wyzant
We take derivative of each function and set it equal to zero.. This also allows us to find the critical point on the graph which can be used to determine the minimum and maximum points.
Part a)
[(x2 - x)1/2]' = 0
(1/2)(x2 - x)-1/2(2x - 1) = 0
(x - (1/2)) / √(x2 - x) = 0
The critical point is x = 1/2
Part b)
(xe-x)' = 0
e-x - xe-x = 0
e-x (1 - x) = 0
The critical point is x = 1