Raymond B. answered 01/28/21
Math, microeconomics or criminal justice
let y=secx
3y^2 -4y - 4 =0
factor
(3y+2)(y-2) = 0
set each factor =0 and solve for y
3y+2 = 0, 3y=-2, y =-2/3
y-2 = 0, y=2
secx=2, 1/cosx =2, cosx = 1/2, x=pi/3 or 2pi/3
secx =2/3, 1/cox=2/3, cosx = 3/2 which is impossible, as cosines are never greater than 1
only solutions are x=pi/3 and 2pi/3
Jeremy C.
Thank you so much!!! I've been stuck on this question for a whole eternity.01/28/21