Calculate the heat change in joules for freezing 295 g of water at 0c

Answer 1

This represents a phase change of water from liquid to solid @0ºC

The ∆Hfusion for water = 334 J/g

295 g x 334 J/g = 98,530 J = 98.53 kJ (sign would be negative as heat is lost from the liquid water)