If Kc = 0.0028 for the reaction below at 298 K, then what is the value of Kp? 3 A (g) + B (g) ⇌ C (g) + D (g)

Answer 1

3A(g) + B(g) <==> C(g) + D(g) Kc = 0.0028

Find Kp.

The relationship between Kp and Kc is as follows:

Kp = Kc(RT)^∆n

Kp = ?

Kc = 0.0028

R = 0.0821 Latm/Kmol

T = 298K

∆n = change in number of moles going from reactant to product = 2 - 4 = -2 (note the negative sign)

Kp = (0.0028)(0.0821*298)^-2

Kp = (0.0028)(24.47)^-2

Kp = (0.0028)(0.202)

Kp = 5.66x10^-4