Can someone literally help ASAP!

Question

Given: AB≅BC

DE bisects AB

DE bisects BC

Prove: BD≅BE B AB and BC are segments

/ \

/ \

/ \

D /_____ \ E

/ \

A /_________\ C

Answer 1

Step 1: DE bisects AB and BC : given bisector

Step 2: AD= DB and CE =EB : definition of bisection

Step 3: AB = AD+DB and BC=CE+EB : given segment

Step 4: AB = BC : given

Step 5: AD + DB = CE + EB : substitution (step 3 into step 4)

Step 6: DB + DB = BE + BE : substitution (step 2 into step 5)

step 7: 2* DB = 2 * BE : combines like terms

step 8: BD = BE : division property of equality; divides both sides by 2

symmetric property