J.R. S. answered 01/28/21
Ph.D. University Professor with 10+ years Tutoring Experience
moles H2S(g) = 0.350 g x 1 mol/34 g = 0.0103 moles
PV = nRT
P = nRT/V = (0.0103 mol)(0.0821 Latm/Kmol)(298K) / 5.00 L
P = 0.0504 atm
Elle B.
asked 01/27/21An empty 5.00-L flask is charged with 0.350 g of pure H2S(g), at 25 ∘C.
What is the initial pressure of H2S(g) in the flask?
J.R. S. answered 01/28/21
Ph.D. University Professor with 10+ years Tutoring Experience
moles H2S(g) = 0.350 g x 1 mol/34 g = 0.0103 moles
PV = nRT
P = nRT/V = (0.0103 mol)(0.0821 Latm/Kmol)(298K) / 5.00 L
P = 0.0504 atm
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