find a equation for the perpendicular bisector of the line segment whose endpoints are ( - 8 , 7 ) and ( 4 , 3 )

Answer 1

The midpoint is (-2, 5)

the slope is (7-3)/(-8-4)

= 4/-12

= -1/3

so the perpendicular bisector passes

through (-2,5) and has slope 3

B = y - mx = 5 - (3)(-2)

= 5 + 6

= 11

y = 3x+11