Chemistry Molarity

Question

How many moles of potassium iodide are in 250mL of a 0.500 mol/L solution?? , what is the mass of potassium iodide is in the solution?

Answer 1

Molar mass potassium iodide, KI = 166 g/mol

250 ml = 0.250 L

0.500 mol / L x 0.250 L = 0.125 moles KI needed

mass KI = 0.125 moles KI x 166 g/mol = 20.75 g KI = 20.8 g KI (3 sig. figs.)