How many liters of carbon dioxide at STP will be produced by the reaction of 10 g of NaHCO3?

Question

Balanced equation: 1 NaHCO3 + 1 HCL = 1 CO2 + 1 H2O + 1 NaCl

Answer 1

Recall that at STP, 1 mole of gas = 22.4 L

NaHCO₃ + HCl ==> NaCl + CO₂ + H₂O ... balanced equation

10 g NaHCO₃ x 1 mol NaHCO₃/84 g = 0.119 moles NaHCO₃ present

From the balanced equation and using dimensional analysis we have...

0.119 mole NaHCO₃ x 1 mol CO₂/mol NaHCO₃ x 22.4 L CO₂/mol CO₂ = 2.66 L CO₂ = 3 L CO₂ (1 sig.fig.)