Area of triangle given two sides (a,b) and an included angle (C) is 1/2 * a * b * sin C
Here a= 112 b = 142 and C = 21 so area = 1/2 * 112 *142 * sin(21) = 2849.74
Sada S.
asked 01/22/21Find the areas of the following triangles:
A≈ ?sq. units
Area of triangle given two sides (a,b) and an included angle (C) is 1/2 * a * b * sin C
Here a= 112 b = 142 and C = 21 so area = 1/2 * 112 *142 * sin(21) = 2849.74
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