Solve the triangles with the given parts using Law of Cosines

Question

Solve the triangles with the given parts using Law of Cosines:

 m<b=?

m<c=?

BC=?

Answer 1

BC = sqrt(34² + 27² - 34*27 cos 44°)

To get the angles use the Law of Sines

sin 44°/length of BC = sin B/27 = sin C/34

This is straight forward arithmetic which I will leave to you!