A baseball "diamond" is a square of side length 90 feet. How far is the throw, to the nearest tenth, from home plate to second base?

Answer 1

Hello, Aiden,

If the baseball diamond is in the shape of a square and we want to find the diagonal (home base to second), the diagonal forms the hypotenuse of a right triangle with both sides of 90 feet. Use the Pythagorean Theory to find the distance.

(90)² + (90)² = X²

X² = 16,200

X = 90 2^(1/2) [The square root of 2]

X = 127.3 feet

Bob