The Kp for the reaction A (g) ⇌ 2 B (g) is 0.0730. What is Kp for the reaction 4 B (g) ⇌ 2 A (g)?

Answer 1

The reaction in question is the reverse of 2 times the original

K for the reverse reaction is 1/K_forward

K for doubling the coefficients is K squared

Therefore K in the present condition is 1 / K² of the original...

1 / (0.0730)² = 188