need help with chemistry

Question

If 10.8 molecules of sodium nitrate react with excess iron(lll) chloride, how many moles of iron(lll) nitrite can theoretically be made?

Answer 1

sodium nitrate = NaNO₃

iron(III) chloride = FeCl₃

iron(III) nitrate = Fe(NO₃)₃

Write the balanced equation:

3NaNO3 + FeCl3 ==> Fe(NO3)3 + 3NaCl (NOTE: this reaction does NOT take place because all species are soluble and so a double displacement will not occur).

So, the answer would be that no iron(III) nitrate will be theoretically made.