54.5mL of a 7.25M stock solution of KMnO4 with enough water to make 750mL of a new solution. What is the new concentration of the solution?

Answer 1

Dilution problem:

V1C1 = V2C2 (or V1M1 = V2M2)

V1 = initial volume = 54.5 ml

C1 = initial concentration = 7.25 M

V2 = final volume = 750 ml

C2 = final concentration = ?

(54.5 ml)(7.25 M) = (750 ml)(x M)

x = 0.527 M KMnO₄