J.R. S. answered 01/21/21
Ph.D. University Professor with 10+ years Tutoring Experience
Look at the standard reduction potentials for Al and Ag:
Al3+ + 3e- ==> Al(s) Eº = -1.66 V
Ag+ + e- ==> Ag(s) Eº = +0.80 V
From this we can tell that Ag will be the cathode (reduction) and Al will be the anode.
a) I cannot see the diagram to which you refer, but you can use any salt for the salt bridge as long as it doesn't interfere with the current flow, so don't use anything that can form a gas or a precipitate. I safe choice is usually nitrate salts since they are soluble. You could use KNO3 for example. Direction of electron flow is from anode to cathode.
b) Ag+ e- ==> Ag cathode
Al ===> Al3+ + 3e- anode
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3Ag+(aq) + Al(s) ==> Ag(s) + Al3+(aq) overall equation
Eºcell = 0.80 + 1.66 = +2.46 V
c) The Ag electrode will increase in mass because Ag+ ions are being reduced to solid Ag which add to the mass of the Ag electrode.
d) An electrolytic cell is not needed because the Eºcell is positive meaning the reaction will occur spontaneously so no external source of energy is necessary.