If 2.46 grams of FeO are reacted with 294.63 grams of Al, how many grams of Fe will be produced?

Question

Al + FeO --> Al₂O₃ + Fe

Answer 1

2Al + 3FeO ==> Al₂O₃ + 3Fe ... balanced equation

Find limiting reactant:

moles Al present = 294.63 g x 1 mol Al / 26.98 g = 10.92 moles Al

moles FeO present = 2.46 g x 1 mol FeO / 71.84 g = 0.0342 moles FeO

Clearly, the FeO is in limiting supply as it takes 3 moles for each 2 moles Al in balanced equation.

Theoretical yield of Fe = 0.0342 moles FeO x 3 moles Fe / 3 moles FeO x 55.8 g/mol = 1.91 g Fe