Trigonometry problem

Question

Given that sec(0) =29/square root of 6. Find an exact value: sin(0), cos(0),tan(0),csc(0),cot(0)

Answer 1

cosΘ = √6 / 29 Think √6 is length of adjacent leg. 29 is length of hypotenuse. 6 + b² = 29² , b = √835

sinΘ = √835 / 29. cscΘ = 29 / √835

tanΘ = √835 / √6. cotΘ = √6 / √835