The base of a cube is parallel to the horizon.
If the cube is cut by a plane to form a cross-section, under what circumstance would it be possible for the cross-section be a non-rectangular parallelogram?
when the plane cuts three faces of the cube, separating one corner from the others
when the plane passes through a pair of vertices that do not share a common face
when the plane is perpendicular to the base and intersects two adjacent vertical faces
when the plane makes an acute angle to the base and intersects three vertical faces
not enough information to answer the question