J.R. S. answered 01/20/21
Ph.D. University Professor with 10+ years Tutoring Experience
See my previous answer for explanation.
73.03 g C x 1 mol/12 g = 6.09 moles C
6.13 g H x 1 mol/1 g = 6.13 moles H
20.84 g O x 1 mol/16 g = 1.30 mole O
Dividing by 1.30 we get...
4.68 mol C
4.7 mol H
1.0 mol O
Multiplying all by 3 we get...
14 moles C
14 moles H
3 moles O
Empirical formula = C14H14O3