write y=csc (x) in terms of y= sec (x)

Question

i was working on trig homework and came across a question that i didn't understand how to even begin to approach. It asked us to write y= csc (x) in terms of y= sec (x). any help would be greatly appreciated

Answer 1

Try using this identity

sec(π/2-x) = csc(x)

Answer 2

csc x = 1 / (sin x) = 1/ ( cos (90-x)) = sec(90-x) = sec ( pi/2 - x)