J.R. S. answered 01/20/21
Ph.D. University Professor with 10+ years Tutoring Experience
The question is essentially asking which one has the greatest number of moles of gas.
From the ideal gas equation PV = nRT and rearranging for moles (n) we have..
n = moles = PV/RT and in all cases, volume (V) is 1.00 L so that is constant. R is the gas constant so it, too can be ignored. That leaves us with
n = moles = P/T (recall T is in Kelvin)
1) 1 atm / 273 = 0.00367
2) 1.25 atm / 273 = 0.00458
3) 1 atm / 293 = 0.00341
4) 1.25 atm / 323 = 0.00389
So greatest number of moles is found in 1.00 L of CH4 at 0 °C and 1.25 atm
(note: it doesn't matter what the gas is (CO, Ar, CO2 or CH4) since 1 mole of any gas has the same number of molecules. Also note that you don't have any molecules of Ar, but rather you have atoms)