write the equation of a line that passes through the point (2,6) and its perpendicular to the line y=-4x+8

Answer 1

to find this equation it must be known that a2 into x and 6 into y line perpendicular to -4x+8 would have an inverse slope that is positive so we can set up this equation

y=1/4x+b where b is the base and put in the input 2 for x and output 6 for y to get this

6=1/4(2)+b which is 6=1/2+b and subtract 1/2 on both sides to get 6-1/2=b which is 12/2-1/2=11/2 so the new equation is y=1/4x+11/2 when 2 is put into x it is 1/2+11/2=12/2 which is 6.

Answer 2

then then the slope of the perpendicular line is 1/4

B = y - mx = 6 - (1/4)(2) = 6 - 1/2 = 12/2-1/2 =11/2

y = (1/4)x + 11/2