If 78.2 grams of oxygen (O2) react with plenty of copper Cu, how many moles of copper (II) oxide (CuO) will be produced?

Answer 1

Write the balanced equation:

O₂ + 2Cu ==> 2CuO

Use dimensional analysis and stoichiometry:

78.2 g O₂ x 1 mol O₂/32 g x 2 mol CuO / mol O₂ x 79.5 g CuO/mol = 389 g CuO