Raymond J. answered 01/19/21
Patient with Ability to Explain in Many Ways
The nth partial sum of an arithmetic sequence is determined by Sn = (n/2)[2a1 + (n-1)d] where a1 is the first term, and d is the common difference between terms. From this we simply plug in the values.
n = 15
a1 = 4
d = ?
Since the 3rd term is 8 and the difference between terms is constant, we can deduce that d = 8-4/2 = 2.
So we have S15 = (15/2)[2(4) + (14)(2)] = 270.