J.R. S. answered 01/18/21
Ph.D. University Professor with 10+ years Tutoring Experience
4 CH3NH2 + 9 O2 ==> 4 CO2 + 10 H20 + 2 N2
We can use dimensional analysis and the stoichiometry (mole ratio) of the balanced equation to answer these questions. We will also need molar mass ofCH3NH2, O2, CO2, H2O and N2 which can be determined from the periodic table.
a) 50 g CH3NH2 x 1 mol CH3NH2 /31 g x 9 mol O2 / 4 mol CH3NH2 x 32 g O2/mol O2 = 116 g O2 (120 g)
b) 50 g CH3NH2 x 1 mol CH3NH2 /31 g x 4 mol CO2 / 4 mol CH3NH2 x 44 g CO2/mol = 71 g CO2
c) 50 g CH3NH2 x 1 mol CH3NH2 /31 g x 10 mol H2O / 4 mol CH3NH2 x 18 g H2O/mol = 73 g H2O
d) 50 g CH3NH2 x 1 mol CH3NH2 /31 g x 2 mol N2 / 4 mol CH3NH2 x 28 g N2 / mol = 23 g N2