Area of triangle given two sides (a and b) and an included angle (<C) is 1/2*a*b*sin(C)
Here a=8, b=11 and m<C = 27
so area = 1/2*8*11*sin(27) = 19.98
Sada S.
asked 01/15/21In △ABC, m∠A=α, m∠B=β , m∠C=γ. AB = c , AC = b , BC = a. Find the areas of the triangles if the following parts are given. a =8, b =11, γ =27º
Find A
Area of triangle given two sides (a and b) and an included angle (<C) is 1/2*a*b*sin(C)
Here a=8, b=11 and m<C = 27
so area = 1/2*8*11*sin(27) = 19.98
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Sada S.
thanks!01/15/21