Zn+2HCL=ZnCL2+H2

Question

What is the total mass of ZnCL2 produced when 195 g of Zn react completely with 216 g of HCL to produce 6g of H2?

i got 51 g but i don’t think it’s right, how do i do this

Answer 1

Zn + 2HCl ==> ZnCl₂ + H₂ ... balanced equation

Looking at mole ratio of H₂ : ZnCl₂, we see it is 1:1

6 g H₂ x 1 mol H₂/2 g = 3 mole H₂

So, 3 mol ZnCl₂ would have to be produced if 3 mol (6 g) of H₂ were produced.

Mass ZnCl₂ = 3 mol ZnCl₂ x 136 g/mol = 408 g ZnCl₂ (not 51 g)

216 g HCl x 1 mol HCl/36.4 g x 1 mol H2/2 mol HCl = 3 mole H₂ formed as stated in the problem. This is the case since HCl is limiting.