J.R. S. answered • 01/15/21

Ph.D. University Professor with 10+ years Tutoring Experience

Zn + 2HCl ==> ZnCl_{2} + H_{2} ... balanced equation

Looking at mole ratio of H_{2} : ZnCl_{2}, we see it is 1:1

6 g H_{2} x 1 mol H_{2}/2 g = 3 mole H_{2}

So, 3 mol ZnCl_{2} would have to be produced if 3 mol (6 g) of H_{2} were produced.

Mass ZnCl_{2} = 3 mol ZnCl_{2} x 136 g/mol = 408 g ZnCl_{2} (not 51 g)

216 g HCl x 1 mol HCl/36.4 g x 1 mol H2/2 mol HCl = 3 mole H_{2} formed as stated in the problem. This is the case since HCl is limiting.

Isabel C.

thank u very much01/15/21