J.R. S. answered 01/15/21
Ph.D. University Professor with 10+ years Tutoring Experience
Arrhenius Equation:
ln(k2/k1) = -Ea/R(1/t2 - 1/T1)
We essentially want to find the ratio of k2 to k1 with k2 being the rate constant at temperature 2 (343) and k1 being the rate constant at temperature 1 (319K). We can set k1 = 1 for this purpose.
ln(k2/k1) = (-42,200 J/mol)/(8.314 J/molK) * (1/343 - 1/319)
ln(k2/k1) = -5076 (-0.00021)
ln (k2/1) = 1.066 = ln k2
k2 = 2.9
So, rate is 2.9 (almost 3x) times faster at 343K than at 319K (assuming my math is correct. Check it carefully)