Statistics math problem

Question

Company XYZ has 114 employees. 26 of the employees are vegetarian, 26 of the employees own a Nissan Leaf and 10 of the employees are vegetarian and own a Nissan Leaf. If you randomly select an employee from company XYZ, what is the probability that the employee is not vegetarian and she/he does not own a Nissan Leaf?

Round your answer to two decimal places.

Answer 1

P(non-vegetarian and no Nissan Leaf) = P(non-vegetarian) x P(no Nissan Leaf)

P(non-vegetarian) = 1 - P(vegetarian) = 1 - (26/114) = 0.772

P(no Nissan Leaf) = 1 = P(Nissan Leaf) = 1 - (26/114) = 0.772

P(non-vegetarian and no Nissan Leaf) = (0.772) x (0.772) = 0.596 = approximately 0.60