write an equation of the line that passes through the point P and is parallel to the line with the given equation: P(2,6); y=5x+2

Answer 1

The slope of the given line y = 5x+2 is 5.

So the slope of the parallel line will also be 5

It passes through point P (2,6)

Using the point slope formula y - y1 = m (x-x1) with m = 5, x1 = 2, y1=6 gives

y - 6 = 5 (x-2) (1)

y = 6 + 5 (x-2)

y = 5x -4 (2)

So (1) and (2) are equivalent equations for the parallel line