Empirical Formula Practice

Question

A compound containing tellurium and fluorine is decomposed in the laboratory and produces 3.605  of tellurium and 3.221  of fluorine.

Calculate the empirical formula of the compound.    

Express your answer as a chemical formula.

Answer 1

You left out the units for Te and for F. I'll assume them to be grams.

3.605 g Te x 1 mol Te / 127.6 g = 0.02825 moles Te

3.221 g F x 1 mol F / 18.99 g = 0.1696 moles F

0.02825 / 0.02825 = 1.00

0.1696 / 0.02825 = 6.00

Mol ratio is 1 mol Te : 6 mol F

Empirical formula = TeF₆