How much work is required to move a 50n box 2meters

Answer 1

James is right, but i would comment if you move the box on floor with constant velocity there will be no work.

W=Fd cos(theta)

1. sum of force F = Fa-f =0 when moving with constant velocity. here Fa is applied force and f is a frictional force. then work done by the net horizontal force =0.
2. If theta = 90 degree between weight of the box 50N and displacement of 2m, then work done by the gravity =0.

Answer 2

Nina, it depends on the direction it’s being moved the 2m, if being lifted straight up the work would equal the gravitational potential, mgh, so 50 x 2 = 100Nm = 100 J. To slide 2m across the level floor the force applied

F_a x 2m would equal the work.