Sunil K. answered 01/10/21
Experienced tutor for intro. to upper level of physics
No. of mole, n = mass of substance / Molar mass = m/M.
Each mole contains Avogadro's No. , Na of molecules.
1st. m = 3.9 g, M = 22.99 + 35.45+16.00 = 74.44 g/mol.
now find n, and each moles has a Na number of molecules.
Therefore, # molecules = n Na.
2nd. m = 2.4 g, M = 12.01+(16.00*2) = 44.01 g/mol
Find n now. Each molecules has Na number of molecules.
Therefore # molecules = nNa.
again each molecule has 2 O atom.
Therefore, # O atom = 2 * n * Na
3rd. Na = 6.02 *10^23 entities.
So 6.02 *10^23 molecules of CH3COONa = M = 82.03 g.
x molecules has M/x g.
Use similar concept to solve rest of your problems.