Statistics Question

Question

The population of weights of a particular fruit is normally distributed with a mean of 601 g and a standard deviation of 34 g of 22 fruit or picked it rain in the 18% of the time they’re mean weight will be greater than how many grams ?round your answer to the nearest gram.

Answer 1

xbar = mean weight

z = (xbar - mean)/(SD/sqrt(sample size))

z for 0.18 percent = -0.915

mean = 601

SD = 34

sample size = 22

plug there values into equation and solve for xbar:

-0.915 = (xbar - 601)/(34/sqrt(22)

-0.915*(34/sqrt(22)) + 601 = xbar

594.37 = xbar