line segment xy has endpoints x(5,-2)and y(-7,0) find the equation of the perpendicular bisector of line segment xy

Answer 1

midpoint at (-1, -1)

slope is (0 - -2) / (-7-5)

= 2/-12

= -1/6

perpendicular has slope 6

B = y - mx = -1 - 6*(-1)

= -1 - -6

= -1 + 6

= 5

y = 6x+5

Answer 2

the bisector goes through the midpoint (-1,-1) average of the end point coordinates

a perpendicular line has slope = negative inverse of the line segment slope (0--2)/(-7-5) = -2/12 = -1/6 flip it upside down and change the sign to get 6

6 = (y+1)(x+1)

y+1 + 6x + 6

y = 6x+5