Raymond B. answered 01/06/21
Tutor
5
(2)
Math, microeconomics or criminal justice
Area of 1st = piR^2
Area of 2nd = pi(4R/9)^2 = 16/81piR^2
ratio = piR^2/(16/81)piR^2= 81/16
John V.
asked 01/06/21The radius of one circle is R, and the radius of the second circle is 4R/9. What is the ratio of the area of the first circle to the area of the second circle?
Raymond B. answered 01/06/21
Math, microeconomics or criminal justice
Area of 1st = piR^2
Area of 2nd = pi(4R/9)^2 = 16/81piR^2
ratio = piR^2/(16/81)piR^2= 81/16
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